7[6x+2-3(x+1)]=4x-2

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Solution for 7[6x+2-3(x+1)]=4x-2 equation:


Simplifying
7[6x + 2 + -3(x + 1)] = 4x + -2

Reorder the terms:
7[6x + 2 + -3(1 + x)] = 4x + -2
7[6x + 2 + (1 * -3 + x * -3)] = 4x + -2
7[6x + 2 + (-3 + -3x)] = 4x + -2

Reorder the terms:
7[2 + -3 + 6x + -3x] = 4x + -2

Combine like terms: 2 + -3 = -1
7[-1 + 6x + -3x] = 4x + -2

Combine like terms: 6x + -3x = 3x
7[-1 + 3x] = 4x + -2
[-1 * 7 + 3x * 7] = 4x + -2
[-7 + 21x] = 4x + -2

Reorder the terms:
-7 + 21x = -2 + 4x

Solving
-7 + 21x = -2 + 4x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4x' to each side of the equation.
-7 + 21x + -4x = -2 + 4x + -4x

Combine like terms: 21x + -4x = 17x
-7 + 17x = -2 + 4x + -4x

Combine like terms: 4x + -4x = 0
-7 + 17x = -2 + 0
-7 + 17x = -2

Add '7' to each side of the equation.
-7 + 7 + 17x = -2 + 7

Combine like terms: -7 + 7 = 0
0 + 17x = -2 + 7
17x = -2 + 7

Combine like terms: -2 + 7 = 5
17x = 5

Divide each side by '17'.
x = 0.2941176471

Simplifying
x = 0.2941176471

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